Question 1182085
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In the 2003 football season, Emmit carried the football 29 times more than Barry and 51 times less than Ricky. 
If the three running backs carried the ball 742 times, how many times did Barry carry the ball?
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<pre>

    Emmit  + Barry +    Ricky     = 742


    (B+29) +  B    + ((B+29) +51) = 742


Simplify and solve


        3B  + 29  + 29 + 51      = 742


        3B       +   109         = 742

        3b                       = 742 - 109

        3B                       = 633

         B                       = 633/3 = 211.      <U>ANSWER</U>
</pre>

Solved.