Question 2075
 Assume the quadratic function (parabloa) is

 y = ax^2 +bx + c,
 Solve: 2 = 0+0+c =c...(1)
        0 = 9a + 3b + c ...(2)
        2 = 25a + 5b + c...(3)
 Replace c by 2,(2),(3) become
 9a + 3b + 2 =0 ...(2)
 5a + b = 0...(3)

 From (3): b =-5a, and goto (2), we have:
 9a - 15a+ 2 =0, or -6a = -2, a = 1/3.
 So, b = -5/3.
 Hence, the function is y = x^2/3 - 5x/3 + 2

 Also,if you notice that the parabola passing (0,2) & (5,2)(same y value)
 Let y = k(x - 0)(x-5) + 2,
 Set x =3, we have 0 = k*3*(-2) + 2, so k = 1/3.
 Thus,we obtain the same answer y = x(x-5)/3 + 2 = x^2/3 - 5x/3 + 2


 Kenny