Question 1182018
{{{system(c+r+b=100,25c+35r+25b=3000,c+b=r)}}}


You can simplify and solve the system.

Maybe see something neat you can do with equation #2 and equation #3.


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This part of the system:
{{{system(c+r+b=100,c+b=r)}}}


{{{system(c+b+r=100,c+b=r)}}}

Substitute for r.

{{{r+r=100}}}

{{{2r=100}}}

{{{highlight(r=50)}}}
and maybe you can find your own way to get values for c and b.