Question 1181909
Zeros:  -3  and +1
Included Point:  (-1,-8)


Start Equation,  {{{y=a(x+3)(x-1)}}}


Use the included point:  {{{-8=a(-1+3)(-1-1)}}}
{{{-8=a(2)(-2)}}}
{{{a=-8/(-4)}}}
{{{a=2}}}


{{{highlight(y=2(x+3)(x-1))}}}