Question 1181911


{{{(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2}}}

Prove that the equation is true.(hint: try using a difference of squares)

{{{(2xy)^2=(x^2+y^2)^2-(x^2-y^2)^2}}}

{{{(2xy)^2=x^4 + 2 x^2 y^2 + y^4-(x^4 - 2 x^2 y^2 + y^4)}}}

{{{(2xy)^2=x^4 + 2x^2 *y^2 + y^4-x^4 + 2x^2*y^2 - y^4}}}

{{{(2xy)^2=2x^2 *y^2 + 2x^2*y^2}}}

{{{(2xy)^2=4x^2*y^2}}}

{{{(2xy)^2=(2xy)^2}}}