Question 1181871
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Equation  0 = {{{2sin(theta)}}}  is equivalent to  {{{sin(theta)}}} = 0,


which has the general solution  {{{theta}}} = {{{k*pi}}}  radians,  where k is any integer number  k = 0, +/- 1, +/- 2, . . . 



Or, in the degrees form,  {{{theta}}} = k*180°.



One formula (in radians or in degrees) works for all possible solutions.
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Solved, and carefully explained.