Question 111316


Let first consecutive integer be {{{x}}}, and let second consecutive integer be {{{y = x+1}}}

Then:
{{{3x + 7y = 97}}}


{{{3x + 7(x+1) = 97}}}

{{{3x + 7x + 7 = 97}}}….move {{{7}}} to the right


{{{ 10x  = 97 - 7}}}

{{{ 10x  = 90}}}………..divide both sides by {{{10}}}

{{{ 10x/10  = 90/10}}}………..

{{{ x  = 9}}}………..first consecutive integer

Now find second consecutive integer

{{{y = x+1 = 9 + 1}}}

{{{y = 10}}}……………….. second consecutive integer


Check:

{{{3x + 7y = 97}}}

{{{3*9 + 7(10) = 97}}}

{{{27 + 70 = 97}}}