Question 1181760
Suppose {{{f(x)=x^2-5x+c}}}  and ​{{{g(x) = f(x)/4 -4}}}.

Find 

{{{f(2)}}} if {{{g(-1)=1}}}


if ​{{{g(-1)=1}}}, then


{{{1= f(-1)/4-4}}}

{{{f(-1)=5*4}}}

{{{f(-1)=20}}}


then use it to calculate {{{c}}} 

{{{f(x)=x^2-5x+c}}}

{{{20=(-1)^2-5(-1)+c}}}

​{{{20 =1 + 5 + c}}}

{{{c=14}}}


your functions {{{f(x)}}} and {{{g(x)}}} are

​{{{f(x) = x^2 - 5x +14}}}

and

{{{g(x) = (x^2 - 5x +14)/4 - 4}}}

{{{g(x) =x^2/4 - (5x)/4 - 1/2}}}


and finally we can calculate {{{f(2) }}}:


​{{{f(2) = 2^2 - 5*2 +14}}}

​{{{f(2) = 4 - 10 +14}}}

{{{f(2) =  - 6 +14}}}

​{{{f(2) = 8}}}