Question 111311
If {{{y=x^2-2x+3}}} and {{{y=x^2-x-2}}}, then,

{{{x^2-2x+3=x^2-x-2}}}
{{{x^2-x^2-2x+3=x^2-x^2-x-2}}}
{{{0-2x+3=0-x-2}}}
{{{-2x+3=-x-2}}}
{{{-2x+x+3=-x+x+2}}}
{{{-x+3=0+2=2}}}
{{{-x+3-3=2-3}}}
{{{-x+0=-1}}}|
{{{-x=-1}}}
{{{x=1}}}

But, {{{y=x^2-2x+3}}}. So,
{{{y=1^2-2*1+3=1-2+3=-1+3=2}}}
Thus, x=1, and y=2,


Power up,
HyperBrain!