Question 1181597
---------------------------------------------------------------------------
the smallest positive x-value for the function {{{cross(y= where)}}} f(x) = 5x^2 - 25
---------------------------------------------------------------------------


This is a parabola with its minimum point vertex.  Smallest possible x value will be at the vertex of f.


The vertex occurs in the exact middle of the zeros of f.
{{{0=5x^2-25}}}
{{{0=x^2-5}}}
{{{x^2=5}}}
{{{x=0+- sqrt(5)}}}
but this much algebraic steps not needed.  THE VERTEX AND MINIMUM OF f OCCURS AT {{{highlight(x=0)}}}.