Question 1181602

{{{x(x-a)(x+b)(x-c) <=0}}}, if {{{a>b>c>0}}}



=> all solutions

{{{x <=0}}}
{{{x <=a}}}
{{{x<=-b}}}
{{{x <=c}}}

so, all combinations are

{{{a>0}}}, 
{{{0<b<a}}}, 
{{{0<c<b}}}, 
{{{-b<=x<=0}}}

or
{{{a>0}}}, 
{{{0<b<a}}}, 
{{{0<c<b}}}, 
{{{c<=x<=a}}}


Interval notation:
({{{0}}}, {{{infinity}}})
({{{0}}}, {{{a}}})
({{{0}}}, {{{b}}})
[{{{-b}}},{{{ 0}}}]
({{{0}}}, {{{infinity}}})
[{{{c}}},{{{ a}}}]



your option: if  {{{a>b>c>0}}}

c. [{{{-b}}},{{{0}}}] and [{{{c}}},{{{a}}}]