Question 1181493
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Especially if you are just learning basic algebra, you should understand how to solve the problem as shown by the other tutor:<br>
determine the slope of the given line;
determine the slope of the line perpendicular to the given line; and
find the equation of the line with that slope passing through the given point.<br>
Here is a more advanced method that is faster and easier.<br>
Any line parallel to the given line 6x-7y-1=0 will have an equation in standard form of 6x-7y+C=0, where C can be any constant  (the coefficients of x and y will be the same as in the given equation).<br>
Any line perpendicular to the given line 6x-7y-1=0 will have an equation in standard form of 7x+6y+D=0, where again D is some constant.  Note to get that form, the coefficients of x and y switch places, and one of them changes sign.<br>
Use that form and the given point (0,-2) to determine the constant.<br>
7(x)+6(y)+D=0
7(0)+6(-2)+D=0
-12+D=0
D=12<br>
ANSWER: 7x+6y+12=0<br>