Question 1181432
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In this problem, the ball participates in two movements, at the same time.

Vertically, the ball falls with uniform acceleration g (the free fall acceleration, or gravity acceleration).

Horizontally, it moves uniformly with the constant horizontal speed.



In vertical direction, we have free fall, so


    H = {{{(gt^2)/2}}},


where  H is the height in meters,  g = 9.81 m/s^ is the gravity acceleration, t is the time of falling.


From this formula,


    t = {{{sqrt((2H)/g)}}} = {{{sqrt((2*12)/9.81)}}} = 1.56 seconds  (rounded).


It is the answer to the first question.


In horizontal direction, the travel is UNIFORM. THEREFORE, the horizontal traveled distance is


    {{{V[horizontal]*t}}} = 12 * 1.56 = 18.72 meters.


It is the answer to the second question.
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Solved.


My solution is a standard mantra to pronounce it every time, when you solve similar problem.