Question 1181404
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (2i\,-\,j)\ +\ (7i\,+\,7j)\ =\ 9i\,+\,6j]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (9i\,+\,6j)\ +\ (-3i)\ =\ 6i\,+\,6j]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 0\ -\ (6i\,+\,6j)\ =\ -6i\,-\,6j]


																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish.jpg]

From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
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