Question 1181395
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A car has uniformly accelerated from rest to a speed of 25m/s after traveling 75m.
what is it's acceleration?
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<pre>
We have two basic kinematic equation for the given situation

    S = {{{(at^2)/2}}}    (1)   (S is the distance, "a" is the acceleration, t is the time)

and

    V = at        (2)    (V is the speed).



Substitute the given values into equations:


    75 = {{{(at^2)/2}}}      (1')

    25 = at          (2')


From (2')  express  t = {{{25/a}}}.   Substitute it into (1').  You will get


    75 = {{{(a*(25/a)^2)/2}}} = {{{625/(2a)}}}.


It gives  a = {{{625/(2*75)}}} = {{{625/150}}} = {{{25/6}}} = 4 {{{1/6}}} m/s^2 = 4.166... m/s^2 = 4.166 m/s^2   (rounded).


<U>ANSWER</U>.  The acceleration is  4 {{{1/6}}} m/s^2 = 4.166... m/s^2 = 4.166 m/s^2   (rounded).
</pre>

Solved.