<PRE><B>Question 1181305</B>
&lt;br&gt;
a) sample space&lt;br&gt;
(1) tails
(2) heads; 2 red
(3) heads; 1 red and 1 blue
(4) heads; 2 blue&lt;br&gt;
b) P(heads; 1 red and 1 blue)&lt;br&gt;
P(heads) = 1/2&lt;br&gt;
Once the heads is obtained, the probability of choosing 1 of the 3 blue and 1 of the 2 red is&lt;br&gt;
{{{(C(3,1)*C(2,1))/C(5,2) = (3*2)/10 = 6/10 = 3/5}}}&lt;br&gt;
So P(heads; 1 red and 1 blue) = (1/2)(3/5) = 3/10.&lt;br&gt;
ANSWER: 3/10&lt;br&gt;
NOTE: If you are just learning to solve probability problems like this, it is a good exercise to calculate the probabilities of all the outcomes in the sample space and verify that the sum of all the probabilities is 1.&lt;br&gt;
</PRE>