Question 1181394
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A rectangle with fixed perimeter has maximum area when the rectangle is a square.<br>
Given 440 feet of fencing, the maximum area is when the length and width are both 440/4=110 feet.<br>
Here is a quick way to show this algebraically....<br>
The perimeter is 440 feet, so length plus width is 220 feet.<br>
To make the sum of length and width equal to 220, let the length be 110+x and the width be 110-x.  Then the area is length times width: (110+x)(110-x)=12100-x^2.<br>
x^2 is always 0 or positive; so the maximum area is when x is 0, making the length and width both 110 feet.<br>