Question 1181370


{{{2cos^2 (theta) =cos( theta)}}}

{{{2cos^2(theta)-cos( theta) =0}}}

{{{(2cos(theta)-1)cos( theta) =0}}}

solutions:

{{{cos( theta) =0}}}

{{{theta =cos^-1( 0)}}}

{{{theta =pi/2}}}


{{{2cos(theta)-1=0}}}

{{{cos(theta) =1/2}}}

{{{theta=cos^-1(1/2) }}}

{{{theta=pi/3}}}


cosine periodicity is {{{2pi}}}


 all the solutions:

{{{theta=pi/3+2pi*n}}}

{{{theta=5p/3+2pi*n}}}

{{{theta=pi2+2pi*n}}}

{{{theta=3pi/2+2pi*n}}}

Degrees:

{{{theta=60+360}}}°*{{{n}}}
{{{theta=300+360}}}°*{{{n}}}
{{{theta=90+360}}}°*{{{n}}}
{{{theta=270+360}}}°*{{{n}}}