Question 1181378
A positive integer is 5 less than another.

let one integer be x
the other (x-5)

the reciprocal of the smaller integer is subtracted from twice the reciprocal of the larger,

2/x  - 1/(x-5) = 7/204

(2(x-5)-x)/x(x-5) =7/204

(2x-10-x)/(x^2-5x) =7/204

(x-10)*204 = 7(x^2-5x)

204x -2040 =7x^2 -35x 

7x^2-239x +2040=0

Solve the quadratic 
the numbers are 17 & 12