Question 1181278


Which term of the geometric sequence 6, 18, 54, … is 118 098?

nth term formula is

{{{a[n]=a[1]*r^(n-1)}}}

{{{a[1]=6}}}
{{{a[2]=18}}}

=>{{{r=18/6=3}}}

and your formula is:

{{{a[n]=6*3^(n-1)}}}

Which term of the geometric sequence is {{{118098}}}

{{{118098=6*3^(n-1)}}}....solve for {{{n}}}

{{{118098/6=3^(n-1)}}}

{{{19683=3^(n-1)}}}........... {{{19683=3^9}}} 

{{{3^9=3^(n-1)}}}.........if base same, exponents are same too

{{{9=(n-1)}}}

{{{9+1=n}}}

{{{n=10}}}

=>{{{118098}}} is {{{10}}}th term of the given geometric sequence