Question 1181261
Let v0= the initial speed = 11 m/s
Then the time to reach maximum height = t = v0sin(20)/g = 0.3835 s
The total flight time = t_tot = 2*0.3835 = 0.7670 s
The max. height h = (v0sin(20))^2/(2g) = 0.7214 m
The range in the horizontal direction = v0cos(20)*t_tot = 11*0.9397*0.767 
= 7.928 m