Question 1181200


{{{find the inverse of {{{f(x)=2x^3+1}}}

recall that {{{f(x)=y}}}

{{{y=2x^3+1}}}......swap variables

{{{x=2y^3+1}}}.........solve for {{{y}}}

{{{x-1=2y^3}}}

{{{(x-1)/2=y^3}}}

{{{y=root(3,(x-1)/2)}}}

inverse is

{{{f}}}'{{{(x)=root(3,(x-1)/2)}}}