Question 1181185
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(2)\ =\ ac^2\ =\ 15]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ c\ =\ \sqrt{\frac{15}{a}}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(4)\ =\ ac^4\ =\ \frac{15}{4}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ c\ =\ \sqrt[4]{\frac{15}{4a}}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \sqrt{\frac{15}{a}}\ =\ \sqrt[4]{\frac{15}{4a}}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{225}{a^2}\ =\ \frac{15}{4a}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 15a\ =\ 900]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a\ =\ 60]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 60c^2\ =\ 15]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ c\ =\ \frac{1}{2}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ f(x)\ =\ 60\(\frac{1}{2}\)^x]





																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish.jpg]

From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
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