Question 1181173
L = R30, lower priced coffee
H = R51, higher priced coffee
x,  how much of the higher priced coffee to use
M = 50 kilograms
M-x, quantity of lower priced coffee to use
T = R42.6, price of mixture


{{{Hx+L(M-x)=TM}}}, equation to account for the cost of the mixture.

{{{Hx+LM-Lx=TM}}}

{{{Hx-Lx=TM-LM}}}

{{{(H-L)x=TM-LM}}}

{{{highlight(x=(TM-LM)/(H-L))}}}


Substitute the given values for M, T, H, and L.  Evaluate x and M-x.


{{{x=50((42.6-30)/(51-30))}}}

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