Question 1181174
<br>
Let x be the second number; then the first number is 5x+3.<br>
The difference between their squares is 45:<br>
{{{(5x+3)^2-x^2=45}}}
{{{25x^2+30x+9-x^2=45}}}
{{{24x^2+30x-36=0}}}
{{{4x^2+5x-6=0}}}
{{{(4x-3)(x+2)=0}}}<br>
x = 3/4  or  x=-2; we want the integer solution.<br>
ANSWER: x=-2; 5x+3=-7<br>