Question 1181125
cos A = 3/5,  A is in Quadrant 1 
sin A =4/5 , cos A = 3/5  , tan A =4/3


tan B = 12/5, quadrant IV

tan B = -12/5, sin B = -12/13 , cos B = 5/13

Sin (A + B) = sin(a)cos(b) + cos(a)sin(b)
 = (4/5)(5/13) +(3/5)(-12/13)
= 20/65 - 36/65
-16/65


sin(A − B) = sin A cos B − cos A sin B

=(4/5)(5/13) -(3/5)(-12/13)
56/65

cos(A + B) = cos A cos B − sin A sin B 
cos(A − B) = cos A cos B + sin A sin B 
sin(A + B) = sin A cos B + cos A sin B 

Plug values and continue