Question 111168
if the {{{larger _number = x}}} is {{{9}}} more than {{{four}}}{{{ times}}}  {{{smaller_number = y}}}, then we have:

{{{x = y + 9}}}

If the {{{x}}} is increased by {{{4y}}}, the result is {{{40}}}, we have:

{{{x + 4y = 40}}}……….now we can plug in the value for {{{x}}} from above, and we will have:

{{{ y + 9 + 4y = 40}}}…………………….solve for {{{y}}}

{{{  9 + 5y = 40}}}………………………….move {{{9}}} to the right

{{{  5y = 40 - 9}}}

{{{  5y = 31}}}

{{{  y = 31}}}

{{{  y = 6.2}}}

Now find {{{x}}}: go back to this formula {{{x = y + 9}}} and plug in the value for {{{y}}}

{{{x = y + 9}}}

{{{x = 6.2 + 9}}}

{{{x = 15.2 }}}


Check:

{{{x + 4y = 40}}}……….plug in {{{x}}} and {{{y}}} values

{{{15.2  + 4*6.2  = 40}}}………

{{{15.2  + 24.8= 40}}}……….

{{{40 = 40}}}