Question 1181029
The mass of brass is equal to the volume of the cube minus the hole times the
density of brass
The mass of lead is equal to the volume of the hole times the density of lead
The volume of the cube = 8^3 = 512 in^3
The volume of the hole = pi*r^2*l = pi*(3/2)^2*6 = 41.412 in^3
Convert the densities to lb/in^3. 1 ft^3 = 1728 in^3
525 lb/ft^3 = 525/1728 = 0.30382 lb/in^3; 705 lb/ft^3 = 0.40799 lb/in^3
Thus the mass of brass = (512 - 41.412)*0.30382 = 142.974 lb
The mass of lead = 41.412*0.40799 = 16.896 lb