Question 1181049


{{{(Area of triangle JKL/area of triangle JKL ) JK^2/GH^2}}}

By property of ratios of areas of similar triangles

{{{(27/area of triangle JKL )= JK^2/GH^2}}}

{{{(27/area of triangle JKL )= 6^2/4^2}}}

Area JKL = 4*27/9

Area JKL = 12 cm^2