Question 1181029
mass in cylindrical hole = pi * r^2 * h * density of lead in ounce/cu.in
Mass= Density * volume

1lb/cft = 0.009 ounces/cu. in
705 lb/cft = 6.35 ounces / cu. in

pi*1.5^2 *6*6.35= 269 ounces

Now volume of remaining cube after drilling

8^3 -269= 243 in^3
weight 

243 * 4.86 =1181 ounces