Question 1180971
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The calculation for binomial probability is well defined; you simply need to do the calculations.  You can do that as easily as we can.<br>
I will outline the calculation required for the first problem and leave the actual work for the rest of the problem to you.<br>
(1) 3 successes in 8 trials with p=0.4....<br>
(a) You need to choose 3 of the 8 trials to be the successful ones: C(8,3)
(b) The probability of each of the 3 successes is 0.4: (0.4)^3
(c) The probability of each of the 5 failures is 1-0.4=0.6: (0.6)^5<br>
ANSWER: (C(8,3))*((0.4)^3)*((0.6)^5))<br>
Use a calculator....<br>
The same calculation with different numbers is required for the other two problems.<br>
(2) 2 failures in 6 trials with p=0.6....<br>
Two notes about this one.
(a) 2 failures in 6 trials means 4 successes.
(b) The p=0.6 must be assumed to be the probability of a success<br>
(3) 2 or fewer successes in 9 trials with p=0.4<br>
For this one you will need to do the calculation 3 times -- with 0, 1, or 2 successes -- and add the three probabilities.<br>