Question 111111
(1) 9^x = 3

==> (3^2)^x = 3

==> 3^(2x) = 3

==> 2x = 1  [ as bases are the same, equate the exponents]

==> x = 1/2 [ divide by 2 on both the sides]

(2) 2^(9x-4) = 32

==> 2^(9x-4) = 2^5 [ as 32 = 2^5]

==> 9x - 4 = 5 [ as bases are the same, equate the exponents ]

==> 9x = 5 + 4

==> 9x = 9

==> x = 1


good luck