Question 1180899
that :3x power 4 *(2x) power 3 over 12x power-2 =Ax power n where A and n are integers. Find the value of A and n
Assume its:
{{{(3x^4*(2x)^3)/(12x^-2)}}} = {{{Ax^n}}}
raise the terms in the brackets to ^3
{{{(3x^4*2^3x^3)/(12x^-2)}}} = {{{Ax^n}}}
reciprocal of x gets rid of the neg exponent
{{{(3x^4*8x^3*x^2)/12}}} = {{{Ax^n}}}
Add the exponents of x
{{{(24x^9)/12}}} = {{{2x^9}}}
therefore A=2, n=9