Question 1180909
{{{int((4x^2+7),dx,0,10) }}} = {{{ (4/3)x^3 + 7x }}}, evaluated x=10, <em>minus</em> the evaluation at x=0.
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= {{{ ((4/3)(1000) + 70) - (0 + 0) }}}
= {{{  (4000/3) + 70 }}} 
= {{{ (4000/3) + (210/3) }}}
= {{{  4210/3 }}}