Question 1180848


A square area ={{{(4a)^2=16a^2}}}

a circle of diameter {{{d=2a}}} =>{{{r=a}}}

a circle area={{{a^2*pi}}}

a rectangle of length 2a and width a removed from it 

a rectangle area={{{2a*a=2a^2}}}

the area of the remaining metal in terms of {{{pi}}}:

{{{16a^2-pi*a^2+2a^2)}}}

{{{16a^2-a^2*pi -2a^2}}}

{{{14a^2-a^2*pi }}}