<PRE><B>Question 111084</B>
Standard form {{{((x-h)^2/a^2)+((y-k)^2/b^2)=1}}}
center=(h,k)=(0,0); h=0, k=0
foci=(h+-c,k)=0+-3,0; c=3
vertices=(h+-a,k)=0+-5,0; a=5
b^2=a^2-c^2=25-9=16; b=4
{{{(x^2/25)+(y^2/16)=1}}}
Or we can get an LCD of 400 and multiply that by the equation above to get:
16x^2+25y^2=400
Ed


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