Question 1180720

{{{16}}}, {{{25}}},{{{34}}},{{{43}}}

as you can see, common difference is {{{d=9}}}

so, nth term formula is: 

{{{a[n]=a[1]+d(n-1)}}}... substitute {{{a[1]}}} and {{{d}}}

{{{a[n]=16+9(n-1)}}}

{{{a[n]=16+9n-9}}}

{{{a[n]=9n+7}}}

to find {{{5}}}th substitute {{{5}}} for {{{n}}}

{{{a[5]=9*5+7}}}
{{{a[5]=52}}}

and so on