Question 1180640


the complex number {{{3 + i*sqrt(3 )}}} in its polar form: ({{{r}}}, {{{theta}}})

the complex number {{{a + b*i}}} 

in your case {{{3 + i*sqrt(3 )}}} , {{{a=3}}} and {{{b=sqrt(3 )}}}

then 

{{{r=sqrt(a^2+b^2)}}}
{{{r=sqrt(3^2+(sqrt(3 ))^2)}}}
{{{r=sqrt(9+3 )}}}
{{{r=sqrt(12 )}}}
{{{r=sqrt(4*3 )}}}
{{{r=2sqrt(3 )}}}

{{{theta=tan^-1(a/b)}}}
{{{theta=tan^-1(3/sqrt(3 ))}}}
{{{theta=pi/6}}}

 polar form:

({{{2sqrt(3)}}} , {{{ pi/6}}})