Question 1180546
 2x2 + 3x + 1=0

comparing with ax^2 +bx +c =0

using the Quadratic Formula where
a = 2, b = 3, and c = 1

b^2-4ac=	9	+	-8			
b^2-4ac=	1					
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}						
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}

substitute the values in the formula						
						
x1=(	-3	+	1	)/	4	
x1=	-0.5					
x2=(	-3	-1	) /	4		
x2=	-1					

Now you know thesteps
solve the rest of them