Question 1180542
<pre>
Without using algebra, just basic math:

If all 27 had been nickels, he would have had only $1.35. But he had $1.90.
So the extra 55 cents must have come from the dimes contributing an extra 
5 cents each.  So there must have been 55/5 or 11 dimes.  That means he had
 27-11 or 16 nickels.

With algebra.

{{{system(N+D=27,0.05N+0.10D=1.90)}}}

Solve that system and get the same answer.

Edwin</pre>