Question 1180531
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Find the 3 cube roots of i in polar form.
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<pre>
    i = (1, {{{pi/2}}}) = (1,90°)  in polar form  (the modulus is 1;  the argument is  {{{pi/2}}},  or  90°).



Use deMoivre formula.  The three cubic roots of " i " are



a)  (1, {{{pi/6}}}) = (1,30°);



b)  (1, {{{pi/6 + (2pi/3)}}}) = (1, {{{pi/6 + 4pi/6}}}) = (1, {{{5pi/6}}}) = (1,150°);



c)  (1, {{{pi/6 + (4pi/3)}}}) = (1, {{{pi/6 + 8pi/6}}}) = (1, {{{9pi/6}}}) = (1,270°).
</pre>


Solved and explained.