Question 1180518
 If {{{z = -1 - i}}}, 

then  

{{{z^10 =(-1 - i)^10}}}

{{{(-1 - i)^10=32(cos(pi/2)+i*sin(pi/2))}}}

{{{(-1 - i)^10=32(0+i*1)}}}

{{{(-1 - i)^10=32i}}}=>the polar form


{{{r = 32}}} (radius), {{{theta = pi/2 }}}(angle)