Question 1180471
If cos t = 3/5 and the terminal point for t is in quadrant IV, find cot t + csc t.
<pre>{{{matrix(1,7, cos (t), "=", 3/5, "=", A/H, "=", x/r)}}}
The above indicates a 3-4-5 Pythagorean triple, with "t" in Q IV. Therefore, y = = -4.
We then get: {{{highlight_green(matrix(1,11, cot (t) + csc (t), "=", A/O + H/O, "=", x/y + r/y, "=", 3/(- 4) + 5/(- 4), "=", 8/(- 4), "=", highlight(- 2)))}}}