Question 1180493
Find the equation of the line perpendicular to y = 3x + 1 that passes through the point (9, -5).
Perpendicular slope formula: m1*m2 = -1
m1 = 3 in our equation, find m2, the slope of the perpendicular line
3m2 = - 1
m2 = -1/3
m2 = -1/3 is the slope of the perpendicular line
let the points be
x1 = 9, y1 = -5, use point/slope equation y - y1 = m(x-x1)
y - (-5) = {{{-1/3}}}(x - 9)
y + 5 = {{{-1/3}}}x + 3
y = {{{-1/3}}}x + 3 - 5
y = {{{-1/3}}}x - 2, is the equation

 Give your answer in the form ax + by + c = 0
We would like everything to be a positive integer, mult above by -3
-3y = x + 6
arrange it then as
x + 3y + 6 = 0 is this form
:
:
you can check this by replacing x with 9 and y with -5, see if equality reigns!