Question 111029
You are given the expression:
{{{7x^2+24x+(13/25)x^2-16-2x^2-(3/25)x^2-16}}}.
To solve it, you first collect the like terms:
{{{7x^2-2x^2+(13/25)x^2-(3/25)x^2+24x-16-16}}}
{{{5x^2+(10/25)x^2+24x-32}}}
{{{5x^2+.6x^2+24x-32}}}
Multiply by 10 to remove the decimal place that was created by calculating 10/25 = .6. 
{{{50x^2+6x^2+240x-320}}}
{{{56x^2+240x-320}}}
Now divide by 8 to simplify:
{{{7x^2+30x-40}}}
At this point, you can stop, unless you were told to factor it or use the quadratic equation.