Question 1180466
.
A rectangular chicken yard was built against an existing
shed wall. 30 m of fencing was used to enclose 108 m2.
Find the dimensions of the yard.
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<pre>
Let x be the width perpendicular to the wall, in meters.

Then the length parallel to the wall is  (30 - 2x) meters.


The area is x*(30-2x), and it is 108 m^2, according to the condition.


So,  

    x*(30-2x) = 108

is your area equation to find x.


Simplify

    30x - 2x^2 = 108

    2x^2 - 30x + 108 = 0

     x^2 - 15x + 54 = 0

     (x-6)*(x-9) = 0


There are two roots, 6 and 9, and they BOTH are meaningful.


<U>ANSWER</U>.  There are two solutions.

          One solution is (the width = 6 m perpendicular to the wall, the length is  30-2*6 = 18 m parallel to the wall).

          The other solution is (the width = 9 m perpendicular to the wall, the length is  30-2*9 = 12 m parallel to the wall).
</pre>

Solved.



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Regarding the post by @MathLover1, &nbsp;she made an arithmetic error on the way, &nbsp;so her solution is &nbsp;FATALLY &nbsp;WRONG.


For your safety, &nbsp;ignore her post.