Question 1180422

the length of fencing is {{{40m}}}

divide the fencing equally among lengths and widths

the length is {{{x}}} and the width is {{{y}}}

you have the area divided in {{{4}}} squares and

{{{y=x/4}}}

the length of fencing is {{{x+2y=40}}}...substitute {{{y}}}

{{{x+2(x/4)=40}}}
{{{x+x/2=40}}}
{{{3x/2=40}}}
{{{3x=80}}}
{{{x=80/3}}}

{{{y=(80/3)/4}}}
{{{y=80/12}}}
{{{y=20/3}}}

then, the area is: 

{{{A=(80/3)(20/3)}}}

{{{A=1600/9}}} 

approximately {{{177.8m^2}}}