Question 1180393
Using the trig identity cos(2x) = 1 - 2sin^2(x), we have:
1 - 2sin^2(x) = 1 - sin(x) -> sin(x)(2sin(x) - 1) = 0
This equation is satisfied if either sin(x) = 0 or 2sin(x) = 1
sin(x) = 0 -> x = 0, pi
sin(x) = 1/2 -> x = pi/6, 5pi/6