Question 1180388
Robert and Caleb each had a collection of rocks. Caleb had 2/9 as many rocks as Robert. When Robert lost 40 rocks, Caleb then had twice as many as Robert. How many rocks were in Robert’s collection at first?

Let Robert have initially x rocks
Celeb will have 2x/9 rocks

When Robert lost 40 rocks he had x-40 rocks

Caleb then had twice as many as Robert

2x/9*2  = (x-40)

4x/9 = x-40

4x = 9x -360

5x =360

x= 72