Question 1180267
<br>
{{{-10x^2-60x+8}}}<br>
Factor the leading coefficient out of the x^2 and x terms:<br>
{{{-10(x^2-6x)+8}}}<br>
Complete the square of the expression in parentheses by adding (6/2)^2=9.  In doing that, you have added -10(9)=-90 to the expression, so you have to add +90 outside the parentheses to keep the expression unchanged.<br>
{{{-10(x^2-6x+9)+8+90}}}<br>
Write the expression in parentheses as the square of a binomial:<br>
{{{-10(x-3)^2+98}}}<br>
ANSWERS:
A = -10
h = 3
k = 98<br>